Vertex Form Calculator
Enter a quadratic in standard form, y = ax² + bx + c, to get its vertex form, vertex, axis of symmetry, roots and discriminant.
Standard form to vertex form
y = ax² + bx + c → y = a(x − h)² + k h = −b ÷ 2a, k = c − b² ÷ 4a
The vertex (h, k) is the highest or lowest point of the parabola. If a is positive the parabola opens upward; if negative it opens downward.
Worked example
For y = 2x² − 8x + 6: h = 8 ÷ 4 = 2 and k = 6 − 64 ÷ 8 = −2, so the vertex form is y = 2(x − 2)² − 2. The discriminant is 64 − 48 = 16, giving roots x = 1 and x = 3.
What the discriminant tells you
| b² − 4ac | Roots |
|---|---|
| Positive | Two real roots |
| Zero | One repeated real root |
| Negative | Two complex roots |
Frequently asked questions
How do I find the vertex of a parabola?
Use x = −b ÷ 2a for the x-coordinate, then substitute it into the equation to get y.
What is the quadratic formula?
x = (−b ± √(b² − 4ac)) ÷ 2a. It gives the roots of any quadratic equation.
What is completing the square?
A method of rewriting ax² + bx + c as a(x − h)² + k, which is exactly the vertex form this calculator produces.
Can a quadratic have no x-intercepts?
Yes. If the discriminant is negative, the parabola never crosses the x-axis.
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